Thermodynamics

JEE Main level, single correct, medium

128 of 190

Question 128 of 190

Which one is the correct option for the two different thermodynamic processes ?

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Answer: (B) (c) and (d)

Option (a) is wrong; since in adiabatic process V≠V\neq constant.
Option (b) is wrong, since in the isothermal process

T= constant

Option (c) & (d) matches isotherms & adiabatic formula :

T{V}^{\gamma -1}=constant&\dfrac{{T}^{\gamma }}{{p}^{\gamma -1}}=constant

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