Thermodynamics

JEE Main level, single correct, medium

143 of 190

Question 143 of 190

A cylinder with fixed capacity of 67.267.2 litre contains helium gas at STP. The amount of heat needed to raise the temperature of the gas by 20∘C20^{\circ}C is:
[Given that R=8.31Jmol−1K−1]R=8.31Jmo{l}^{-1}{K}^{-1}]

Show answer and solution

Answer: (A) 748J748J

The amount of heat supplied is
Q=nCVΔTQ=n{C}_{V}\Delta T
=(67.222.4)(3R2)20=\left(\dfrac{67.2}{22.4}\right)\left(\dfrac{3R}{2}\right)20
=3×32×8.314×20=3\times \dfrac{3}{2}\times 8.314\times 20
=748J=748 J

JEE Main question paper PDF

Open a shift to read the full paper on this page, or download it.

JEE Main 2025 Apr 2 Shift 1 question paper

Open Download PDF

Opening paper…

Explain it as a whiteboard videoStep-by-step, in Hinglish or English. Your first video needs no login.Solved it on paper but got it wrong?Upload a photo of your working. Mistake Doctor marks the exact line that broke.

More Physics practice

JEE Main Physics practice question on Thermodynamics (Thermodynamic Processes), with the answer and a step-by-step solution. Scan a question from your own book or paper to get a whiteboard video.