Thermodynamics

JEE Main level, single correct, medium

152 of 190

Question 152 of 190

One mole of an ideal monoatomic gas is compressed isothermally in a rigid vessel to double its pressure at room temperature, 27∘C27^{\circ} \mathrm{C}. The work done on the gas will be:

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Answer: (D) 300Rln⁡2300 \mathrm{R} \ln 2

Work done on gas =nRTℓn(pfp1)=\mathrm{nRT} \ell n\left(\frac{p_f}{p_1}\right)
=R(300)ℓn(2)(∵Pfpi=2 given )=\mathrm{R}(300) \ell \mathrm{n}(2)\left(\because \frac{P_f}{p_i}=2 \text { given }\right)

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