Thermodynamics

JEE Main level, single correct, medium

179 of 190

Question 179 of 190

The net work done on the gas in the cycle ABCDA is

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Answer: (B) 276R276 \mathrm{R}

 Net work done in a cycle =WAB+WBC+WCB+WBA=400R+2×2.303×500Rln⁡2−400R−414R=1000R×ln⁡2−600R×ln⁡2=400R×ln⁡2=276R\begin{aligned} \text { Net work done in a cycle } & =W_{A B}+W_{B C}+W_{C B}+W_{B A} \\ & =400 R+2 \times 2.303 \times 500 R \ln 2-400 R-414 R \\ & =1000 R \times \ln 2-600 R \times \ln 2=400 R \times \ln 2=276 R \end{aligned}

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