Thermodynamics

JEE Main level, single correct, medium

182 of 190

Question 182 of 190

The work of 146 kJ146 \mathrm{~kJ} is performed in order to compress one kilo mole of gas adiabatically and in this process the temperature of the gas increases by 7∘C7^{\circ} \mathrm{C}. The gas is (R=8.3 J mol−1 K−1)\left(\mathrm{R}=8.3 \mathrm{~J} \mathrm{~mol}^{-1} \mathrm{~K}^{-1}\right)

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Answer: (B) diatomic

146=CvΔT146=C_v \Delta T
⇒Cv=21 J/molK\Rightarrow C_v=21 \mathrm{~J} / \mathrm{mol} \mathrm{K}

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