Units & Dimensions

JEE Main level, single correct, medium

3 of 149

Question 3 of 149

Keeping the significant figures in view, the sum of the physical quantities 52.01 m,153.2 m52.01 \mathrm{~m}, 153.2 \mathrm{~m} and 0.123 m is :

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Answer: (A) 205.3 m

When adding measurements, the result must be limited to the least number of decimal places among all quantities.
The measurements are: 52.01 m (2 decimal places), 153.2 m (1 decimal place), and 0.123 m (3 decimal places).

The limiting factor is 1 decimal place.

Calculating the sum: 52.01 + 153.2 + 0.123 = 205.333 m.

Rounding to 1 decimal place gives 205.3 m, which is option (1).

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