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Units & Dimensions

JEE Main level, single correct, medium

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Question 1 of 149

The dimensional formula of magnetic permeability of free space $\mu_0$ is:

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Answer: (B) $[M L T^{-2} A^{-2}]$

Force per unit length

F/L = \frac{\mu_0 I^2}{2\pi d} \implies [M L T^{-2} / L] = [\mu_0] [A^2] / [L] \implies [\mu_0] = [M L T^{-2} A^{-2}]

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More Physics practice

Units & DimensionsA new unit $(\alpha)$ of length is chosen such that it is equal to the speed of light in vacuum. What is the distance between Venus and Earth in terms of $\alpha$ units if light takes $6$ min. $40$ s to cover this distance?
Units & DimensionsKeeping the significant figures in view, the sum of the physical quantities $52.01 \mathrm{~m}, 153.2 \mathrm{~m}$ and 0.123 m is :
Units & DimensionsMatch List-I with List-II.
$\begin{array}{ll} \text{List-I} & \text{List-II} \\ \text{(A) Heat capacity of body} & \text{(I) } \mathrm{J} \mathrm{kg}^{-1} \\ \text{(B) Specific heat capacity of body} & \text{(II) } \mathrm{JK}^{-1} \\ \text{(C) Latent heat} & \text{(III) } \mathrm{J} \mathrm{kg}^{-1} \mathrm{~K}^{-1} \\ \text{(D) Thermal conductivity} & \text{(IV) } \mathrm{Jm}^{-1} \mathrm{~K}^{-1} \mathrm{~s}^{-1} \end{array}$
Choose the correct answer from the options given below :
Units & DimensionsMatch List - I with List - II.

Choose the correct answer from the options given below :
Units & DimensionsMatch List - I with List - II.
$\begin{array}{llll} & \text { List - I } & & \text { List - II } \\ \text { (A) } & \text { Permeability of free space } & \text { (I) }\left[\mathrm{M} \mathrm{~L}^2 \mathrm{~T}^{-2}\right] \\ \text { (B) } & \text { Magnetic field } & \text { (II) }\left[\mathrm{M} \mathrm{~T}^{-2} \mathrm{~A}^{-1}\right] \\ \text { (C) } & \text { Magnetic moment } & \text { (III) }\left[\mathrm{M} \mathrm{~L} \mathrm{~T}^{-2} \mathrm{~A}^{-2}\right] \\ \text { (D) } & \text { Torsional constant } & \text { (IV) }\left[\mathrm{L}^2 \mathrm{~A}\right] \end{array}$

Choose the correct answer from the options given below :
Units & DimensionsGiven below are two statements :
Statement I : Astronomical unit (Au), Parsec (Pc) and Light year (ly) are units for measuring astronomical distances.
Statement II : Au < Parsec (Pc) < ly
In the light of the above statements, choose the most appropriate answer from the options given below:

JEE Main Physics practice question on Units & Dimensions, with the answer and a step-by-step solution. Scan a question from your own book or paper to get a whiteboard video.

The dimensional formula of magnetic permeability of free space μ0\mu_0μ0​ is:

JEE Main question paper PDF

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The dimensional formula of magnetic permeability of free space $\mu_0$ is: