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Wave Optics

JEE Main level, single correct, medium

47 of 191

Question 47 of 191

The Young's double slit interference experiment is performed using light consisting of 480 nm and 600 nm wavelengths to form interference patterns. The least number of the bright fringes of 480 nm light that are required for the first coincidence with the bright fringes formed by 600 nm light is

Show answer and solution

Answer: (A) $5$

\begin{aligned} & \frac{n_1 \lambda_1 D}{d}=\frac{n_2 \lambda_2 D}{d} \\ & n 480=m 600 \\ & n_{\min }=5 \end{aligned}

JEE Main question paper PDF

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JEE Main 2025 Apr 2 Shift 1 question paper

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