Wave Optics

JEE Main level, numerical answer, medium

54 of 191

Question 54 of 191

In a single slit experiment, a parallel beam of green light of wavelength 550 nm550 \mathrm{~nm} passes through a slit of width 0.20 mm0.20 \mathrm{~mm}. The transmitted light is collected on a screen 100 cm100 \mathrm{~cm} away. The distance of first order minima from the central maximum will be x×10−5 mx \times 10^{-5} \mathrm{~m}. The value of xx is :

Show answer and solution

Answer: 275


y=λDd=550×10−9×100×10−20.2×10−3=275\mathrm{y}=\frac{\lambda \mathrm{D}}{\mathrm{d}}=\frac{550 \times 10^{-9} \times 100 \times 10^{-2}}{0.2 \times 10^{-3}}=275

JEE Main question paper PDF

Open a shift to read the full paper on this page, or download it.

JEE Main 2025 Apr 2 Shift 1 question paper

Open Download PDF

Opening paper…

Explain it as a whiteboard videoStep-by-step, in Hinglish or English. Your first video needs no login.Solved it on paper but got it wrong?Upload a photo of your working. Mistake Doctor marks the exact line that broke.
See it move: Wave optics: YDSE, diffraction and polarisation simulationDrag the sliders and watch the numbers in this question change.

More Physics practice

JEE Main Physics practice question on Wave Optics (Youngs Double Slit Experiment), with the answer and a step-by-step solution. Scan a question from your own book or paper to get a whiteboard video.