Wave Optics

JEE Main level, single correct, medium

105 of 191

Question 105 of 191

Light of wavelength 550nm550nm falls normally on a slit of width 22.0×10−5cm22.0\times {10}^{-5}cm. The angular position of the second minima from the central maximum will be (in radians):

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Answer: (D) π6\dfrac{\pi }{6}

asin⁡θ=2λ,2nddarka\sin \theta =2\lambda , {2}^{nd}\text{dark}

⇒sin⁡θ=2λa=2×550×10−922×10−7\Rightarrow \sin \theta =\dfrac{2\lambda }{a}=\dfrac{2\times 550\times {10}^{-9}}{22\times {10}^{-7}}⇒θ≃π6rad\Rightarrow \theta ≃\dfrac{\pi }{6}rad

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