Wave Optics

JEE Main level, single correct, medium

124 of 191

Question 124 of 191

A slit of width aa is illuminated by light of wavelength λ\lambda. The linear separation between 1st1^{st} and 3rd3^{rd} minima in the diffraction pattern produced on a screen placed at a distance DD from the slit system is _____.

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Answer: (C) 2Dλa2\dfrac{D\lambda}{a}

The position of the nthn^{th} minimum in a single slit diffraction pattern on a screen at distance DD is given by yn=nDλay_n = \dfrac{n D \lambda}{a}.

For the
1st1^{st} minimum, n=1n = 1, so y1=Dλay_1 = \dfrac{D \lambda}{a}.

For the
3rd3^{rd} minimum, n=3n = 3, so y3=3Dλay_3 = \dfrac{3 D \lambda}{a}.

The linear separation between the
1st1^{st} and 3rd3^{rd} minima on the same side of the central maximum is Δy=y3−y1\Delta y = y_3 - y_1.

Δy=3Dλa−Dλa=2Dλa\Delta y = \dfrac{3 D \lambda}{a} - \dfrac{D \lambda}{a} = 2\dfrac{D \lambda}{a}.

Answer:
2Dλa2\dfrac{D\lambda}{a}

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