Question 136 of 191

Given below are two statements :
Statement I : If the Brewster's angle for the light propagating from air to glass is ${\theta }_{B}$, then Brewster's angle for the light propagating from glass to air is $\dfrac{\pi }{2}-{\theta }_{B}$.
Statement II : The Brewster's angle for the light propagating from glass to air is ${\tan }^{-1}\left({\mu }_{g}\right)$, where ${\mu }_{g}$ is the refractive index of glass.
In the light of the above statements, choose the correct answer from the options given below :

ABoth Statements I and Statement II are true.BStatement I is true but Statement II is false.CBoth Statement I and Statement II are false.DStatement I is false but Statement II is true.

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Answer: (B) Statement I is true but Statement II is false.

Applying Snell's law, we get
${\mu }_{a}\sin i={\mu }_{g}\sin \left(90^{\circ}-i\right)$
$\tan i=\dfrac{{\mu }_{g}}{{\mu }_{a}}$
When going from glass to air
$\tan {i}^{'}=\dfrac{{\mu }_{a}}{{\mu }_{g}}=\cot i$
Clearly, ${i}^{'}=\left(\dfrac{\pi }{2}-i\right)$ & hence Statement I is true but Statement II is false.