Wave Optics

JEE Main level, numerical answer, medium

140 of 191

Question 140 of 191

Orange light of wavelength 6000×10–10m6000\times {10}^{–10}m illuminates a single slit of width 0.6×10–4m0.6\times {10}^{–4}m. The maximum possible number of diffraction minima produced on both sides of the central maximum is __________

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Answer: 200

Light of wavelength 6000×10–10m6000\times {10}^{–10}m passes through a single slit of width 0.6×10–4m0.6\times {10}^{–4}m. Find height of highest order of minima on both side central maxima
for minima
dsinθ=nλdsin\theta =n\lambda
sinθ=nλd<1sin\theta =\dfrac{n\lambda }{d}\lt 1
n≤dλn\leq \dfrac{d}{\lambda }
n<0.6×10−46000×10−10n\lt \dfrac{0.6\times {10}^{-4}}{6000\times {10}^{-10}}
n<100n\lt 100
The total number of maxima of both side at central maxima =100+100=200=100+100=200

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