Wave Optics

JEE Main level, single correct, medium

152 of 191

Question 152 of 191

In an experiment of single slit diffraction pattern, first minimum for red light coincides with first maximum of some other wavelength. If wavelength of red light is 6600A˚6600 Å, then wavelength of first maximum will be:

Show answer and solution

Answer: (B) 4400A˚4400 Å

In a single slit experiment, For diffraction maxima, asin⁡θ=(2n+1A˚2a \sin \theta=\left(2 n+1 \frac{Å}{2}\right. and for diffraction minima, asin⁡θ=nλ\mathrm{a} \sin \theta=\mathrm{n} \lambda According to question,
(2×1+1λ2=1×6600(∵λR=6600A˚)λ=6600×23λ=4400A˚\begin{aligned} &\left(2 \times 1+1 \frac{\lambda}{2}=1 \times 6600\right. \\ &\left(\because \lambda_{\mathrm{R}}=6600 Å\right) \\ &\lambda=\frac{6600 \times 2}{3} \\ &\lambda=4400 Å \end{aligned}

JEE Main question paper PDF

Open a shift to read the full paper on this page, or download it.

JEE Main 2025 Apr 2 Shift 1 question paper

Open Download PDF

Opening paper…

Explain it as a whiteboard videoStep-by-step, in Hinglish or English. Your first video needs no login.Solved it on paper but got it wrong?Upload a photo of your working. Mistake Doctor marks the exact line that broke.
See it move: Wave optics: YDSE, diffraction and polarisation simulationDrag the sliders and watch the numbers in this question change.

More Physics practice

JEE Main Physics practice question on Wave Optics (Diffraction of Light), with the answer and a step-by-step solution. Scan a question from your own book or paper to get a whiteboard video.