Wave Optics

JEE Main level, numerical answer, medium

177 of 191

Question 177 of 191

An unpolarized light beam is incident on the polarizer of a polarization experiment and the intensity of light beam emerging from the analyzer is measured as 100100 Lumens. Now, if the analyzer is rotated around the horizontal axis (direction of light) by 30∘30^{\circ} in clockwise direction, the intensity of emerging light will be _______Lumens.

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Answer: 75


Assuming initially axis of Polarizer and Analyzer are parallel


Now emerging intensity
=I02cos⁡230∘=\dfrac{{I}_{0}}{2}{\cos }^{2}30^{\circ}
=100(32)2=100×34=75=100{\left(\dfrac{\sqrt{3}}{2}\right)}^{2}=100\times \dfrac{3}{4}=75

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