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Waves

JEE Main level, numerical answer, medium

90 of 142

Question 90 of 142

For a certain organ pipe, the first three resonance frequencies are in the ratio of $1:3:5$ respectively. If the frequency of fifth harmonic is $405Hz$ and the speed of sound in air is $324m{s}^{–1}$ the length of the organ pipe is _____ $m$ .

Show answer and solution

Answer: 1

It is given,

{f}_{5}=405Hz

.
As the first three resonance frequencies are in the ratio of

1:3:5

, therefore it must be a closed organ pipe.
The frequency formula in a closed organ pipe is given by

f=\dfrac{nv}{4l}

. So,

\dfrac{5v}{4I}=405Hz

\Rightarrow I=\dfrac{405\times 4}{5\times 324}=1m

JEE Main question paper PDF

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JEE Main 2025 Apr 2 Shift 1 question paper

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JEE Main Physics practice question on Waves (Organ Pipe (Vibration of Air Column)), with the answer and a step-by-step solution. Scan a question from your own book or paper to get a whiteboard video.

For a certain organ pipe, the first three resonance frequencies are in the ratio of 1:3:51:3:51:3:5 respectively. If the frequency of fifth harmonic is 405Hz405Hz405Hz and the speed of sound in air is 324ms–1324m{s}^{–1}324ms–1 the length of the organ pipe is _____ mmm.

JEE Main question paper PDF

More Physics practice

For a certain organ pipe, the first three resonance frequencies are in the ratio of $1:3:5$ respectively. If the frequency of fifth harmonic is $405Hz$ and the speed of sound in air is $324m{s}^{–1}$ the length of the organ pipe is _____ $m$ .