Waves

JEE Main level, single correct, medium

125 of 142

Question 125 of 142

A tuning fork arrangement (pair) produces 4 beats / sec with one fork of frequency 288cps288 \mathrm{cps}. A little wax is placed on the unknown fork and it then produces 2 beats /sec. The frequency of the unknown fork is

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Answer: (B) 292 cps

The fact that placing wax decreases the frequency of the unknown fork and also the beat frequency states that the unknown fork is of higher frequency.
n−288=4⇒n=292cpsn-288=4 \Rightarrow n=292 \mathrm{cps}

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