Work Energy Power

JEE Main level, numerical answer, medium

9 of 183

Question 9 of 183

A force (3x2+2x−5)N\left(3 x^2+2 x-5\right) \mathrm{N} displaces a body from x=2 mx=2 \mathrm{~m} to x=4 mx=4 \mathrm{~m}. Work done by this force is ________ JJ.

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Answer: 58

W=∫x1x2FdxW=∫24(3x2+2x−5)dxW=[x3+x2−5x]24W=[60−2]J=58J\begin{aligned} & W=\int_{x_1}^{x_2} F d x \\ & W=\int_2^4\left(3 x^2+2 x-5\right) d x \\ & W=\left[x^3+x^2-5 x\right]_2^4 \\ & W=[60-2] J=58 J\end{aligned}

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