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Work Energy Power

JEE Main level, numerical answer, medium

14 of 183

Question 14 of 183

A force $\vec{F}=\left(2+3x\right)\hat{i}$ acts on a particle in the $x$ direction where $F$ is in Newton and $x$ is in meter. The work done by this force during a displacement from $x=0$ to $x=4m$ is _____ $J$ .

Show answer and solution

Answer: 32

The formula to calculate the work done by a variable force is given by

W={\int }_{{x}_{1}}^{{x}_{2}}Fdx...\left(1\right)

Substitute the values of the known parameters into equation (1) to calculate the required work done.

\begin{matrix}W & = & {\int }_{0}^{4}(2+3x)dx \\ & = & {\left[2x+\dfrac{3}{2}{x}^{2}\right]}_{0}^{4} \\ & = & [8+24]J \\ & = & 32J\end{matrix}

JEE Main question paper PDF

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JEE Main 2025 Apr 2 Shift 1 question paper

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More Physics practice

JEE Main Physics practice question on Work Energy Power (Work done), with the answer and a step-by-step solution. Scan a question from your own book or paper to get a whiteboard video.

A force F⃗=(2+3x)i^\vec{F}=\left(2+3x\right)\hat{i}F=(2+3x)i^ acts on a particle in the xxx direction where FFF is in Newton and xxx is in meter. The work done by this force during a displacement from x=0x=0x=0 to x=4mx=4mx=4m is _____ JJJ.

JEE Main question paper PDF

More Physics practice

A force $\vec{F}=\left(2+3x\right)\hat{i}$ acts on a particle in the $x$ direction where $F$ is in Newton and $x$ is in meter. The work done by this force during a displacement from $x=0$ to $x=4m$ is _____ $J$ .