Work Energy Power

JEE Main level, single correct, medium

99 of 183

Question 99 of 183

Given below is the plot of a potential energy function U(x)U(x) for a system, in which a particle is in one dimensional motion, while a conservative force F(x)F(x) acts on it. Suppose that Emech=8J{E}_{\text{mech}}=8J, the incorrect statement for this system is :

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Answer: (B) at x<x1,K.Ex\lt {x}_{1},K.E. is smallest and the particle is moving at the slowest speed.

(A) at x>x4,U=x\gt {x}_{4},U= constant =6J=6J
K=Emech.−U=2J=constantK={E}_{mech.}-U=2J=constant
(B) at x<x1,U=x\lt {x}_{1},U= constant =8J=8J
K=Emech.−U=8−8=0JK={E}_{mech.}-U=8-8=0J
Particle is at rest.
(C) At x=x2,U=0⇒Emech.=K=8Jx={x}_{2},U=0\Rightarrow {E}_{mech.}=K=8J
KEKE is greatest, and particle is moving at fastest speed.
(D) At x=x3,U=4Jx={x}_{3},U=4J
U+K=8JU+K=8J
K=4JK=4J

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