Work Energy Power

JEE Main level, single correct, medium

161 of 183

Question 161 of 183

A particle of mass M is moving in a circle of fixed radius R in such a way that its centripetal acceleration at time t is given by n2Rt2{n}^{2}R{t}^{2}, where nn is a constant. The power delivered to the particle by the force acting on it, is :

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Answer: (B) Mn2R2tM{n}^{2}{R}^{2}t

ac=v2R=n2Rt2{a}_{c}=\dfrac{{v}^{2}}{R}={n}^{2}R{t}^{2}

v=nRTv=nRT

at=dvdt=nR{a}_{t}=\dfrac{dv}{dt}=nR

Power =Matv=M{a}_{t}v

=MnRnRt=MnRnRt

=Mn2R2t=M{n}^{2}{R}^{2}t

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