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Solutions

JEE Main level, single correct, medium

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Question 1 of 4

Assuming $100\%$ dissociation, the van't Hoff factor $i$ for $K_4[Fe(CN)_6]$ in dilute aqueous solution is:

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Answer: (D) 5

K_4[Fe(CN)_6] \rightarrow 4K^+ + [Fe(CN)_6]^{4-}

. Total ions

= 4 + 1 = 5

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JEE Main 2025 Apr 2 Shift 1 question paper

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Assuming 100%100\%100% dissociation, the van't Hoff factor iii for K4[Fe(CN)6]K_4[Fe(CN)_6]K4​[Fe(CN)6​] in dilute aqueous solution is:

JEE Main question paper PDF

More Chemistry practice

Assuming $100\%$ dissociation, the van't Hoff factor $i$ for $K_4[Fe(CN)_6]$ in dilute aqueous solution is: