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Vectors & 3D Geometry

JEE Main level, single correct, medium

2 of 4

Question 2 of 4

The perpendicular distance of the point $(1, 2, 3)$ from the plane $2x - y + 2z = 9$ is:

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Answer: (C) $1$

d = \frac{|2(1) - 2 + 2(3) - 9|}{\sqrt{2^2+(-1)^2+2^2}} = \frac{|-3|}{3} = 1

JEE Main question paper PDF

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JEE Main 2025 Apr 2 Shift 1 question paper

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More Mathematics practice

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JEE Main Mathematics practice question on Vectors & 3D Geometry, with the answer and a step-by-step solution. Scan a question from your own book or paper to get a whiteboard video.

The perpendicular distance of the point (1,2,3)(1, 2, 3)(1,2,3) from the plane 2x−y+2z=92x - y + 2z = 92x−y+2z=9 is:

JEE Main question paper PDF

More Mathematics practice

The perpendicular distance of the point $(1, 2, 3)$ from the plane $2x - y + 2z = 9$ is: