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(घ) सिद्ध कीजिए कि यदि E और F स्वतन्त्र घटनाएँ हैं, तो E और F' भी स्वतन्त्र होंगी। 5. सभी खण्ड कीजिए- (क) सारणिक 17 15 13 9 -8 7 का मान ज्ञात कीजिए। -3 2 5 (ख) दर्शाइए कि sin-1 12/13 + Cos-1 4/5 + tan-1 63/16 = π. (ग) यद

Concept: Independent events and complements

Question

(घ) सिद्ध कीजिए कि यदि E और F स्वतन्त्र घटनाएँ हैं, तो E और F' भी स्वतन्त्र होंगी।
5. सभी खण्ड कीजिए-
(क) सारणिक
17 15 13
9 -8 7 का मान ज्ञात कीजिए।
-3 2 5
(ख) दर्शाइए कि sin-1 12/13 + Cos-1 4/5 + tan-1 63/16 = π.
(ग) यदि x = a sin³t, y = b cos³t तो बिन्दु t = π/2 पर dy/dx ज्ञात कीजिए।

Try it yourself first

Hint: Start by writing down the definition of independent events for E and F, and what you need to show for E and F' to be independent.

Step-by-step solution

  1. 1

    Given condition

    EE and FF are independent events.
    P(E∩F)=P(E)P(F)P(E \cap F) = P(E)P(F)
  2. 2

    Goal for independence

    To prove EE and F′F' are independent, we must show:
    P(E∩F′)=P(E)P(F′)P(E \cap F') = P(E)P(F')
  3. 3

    Relate $E \cap F'$ to $E \cap F$

    The event E∩F′E \cap F' means EE occurs and FF does not occur.
    E∩F′=E−(E∩F)E \cap F' = E - (E \cap F)
  4. 4

    Probability of $E \cap F'$

    Using the property P(A−B)=P(A)−P(A∩B)P(A-B) = P(A) - P(A \cap B):
    P(E∩F′)=P(E)−P(E∩F)P(E \cap F') = P(E) - P(E \cap F)
  5. 5

    Substitute independence

    Substitute P(E∩F)=P(E)P(F)P(E \cap F) = P(E)P(F) from the given condition:
    P(E∩F′)=P(E)−P(E)P(F)P(E \cap F') = P(E) - P(E)P(F)
  6. 6

    Factor out $P(E)$

    Factor out P(E)P(E) from the right side of the equation:
    P(E∩F′)=P(E)(1−P(F))P(E \cap F') = P(E)(1 - P(F))
  7. 7

    Use complement property

    Recall that 1−P(F)=P(F′)1 - P(F) = P(F') (probability of complement event):
    P(E∩F′)=P(E)P(F′)P(E \cap F') = P(E)P(F')
  8. 8

    Conclusion

    Since P(E∩F′)=P(E)P(F′)P(E \cap F') = P(E)P(F'), EE and F′F' are independent.

Final answer

E and F' are independent.

Remember: If two events are independent, one is independent of the other's complement.

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