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Explain loga a clearly: what it is, why/how it happens, the key formula or law with a short worked example, and one common exam trap.

Concept: Logarithm definition

Question

Explain loga a clearly: what it is, why/how it happens, the key formula or law with a short worked example, and one common exam trap.

Try it yourself first

Hint: Think about the definition of a logarithm: what power do you raise the base to, to get the number itself?

Step-by-step solution

  1. 1

    Logarithm definition

    A logarithm answers: 'To what power must the base be raised to get the number?'
    logaN=x  ⟺  ax=Nlog_a N = x \iff a^x = N
  2. 2

    Apply definition to $log_a a$

    Let logaa=xlog_a a = x. We need to find the value of xx.
    logaa=xlog_a a = x
  3. 3

    Convert to exponential form

    Using the definition, logaa=xlog_a a = x can be written as ax=aa^x = a.
    ax=aa^x = a
  4. 4

    Solve for $x$

    Since a=a1a = a^1, we have ax=a1a^x = a^1. Therefore, x=1x=1.
    ax=a1  ⟹  x=1a^x = a^1 \implies x=1
  5. 5

    Key formula

    Thus, logaa=1log_a a = 1. This is a fundamental property of logarithms.
    logaa=1log_a a = 1
  6. 6

    Worked example

    Example: log55=1log_5 5 = 1 because 51=55^1 = 5. Also, log1010=1log_{10} 10 = 1 because 101=1010^1 = 10.
    log55=1 (since 51=5)log_5 5 = 1 \text{ (since } 5^1 = 5)
  7. 7

    Exam trap

    Remember base conditions: a>0a > 0 and a≠1a \neq 1. log11log_1 1 is undefined.
    Base a>0,a≠1\text{Base } a > 0, a \neq 1

Final answer

The logarithm of a number to its own base is always 1.

Remember: Logarithm of a number to its own base is always 1.

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Which of the following expressions is equivalent to logbb3log_b b^3?

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