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Find velocity of car/tank as fx of time.

Concept: Variable mass system

Question

Find velocity of car/tank as fx of time.
F=dpdt=mdvdt+vdmdtF = \frac{dp}{dt} = m \frac{dv}{dt} + v \frac{dm}{dt}

Try it yourself first

Hint: Think about how the total mass of the car/tank changes over time.

Step-by-step solution

  1. 1

    Identify forces

    Force F = Q E₀
    F=QE0F = Q E_0
  2. 2

    Mass at time t

    Initial mass M₀ • Mass added = n m t • Total mass M(t) = M₀ + n m t
    M(t)=M0+nmtM(t) = M_0 + n m t
  3. 3

    Apply Newton's 2nd Law

    F = dp/dt • F = M dv/dt + v dM/dt • dM/dt = n m
    F=MdvdtF = M \frac{dv}{dt}
  4. 4

    Solve differential equation

    Q E₀ = (M₀ + n m t) dv/dt • dv = (Q E₀ / (M₀ + n m t)) dt • Integrate both sides
    ∫dv=∫QE0M0+nmtdt\int dv = \int \frac{Q E_0}{M_0 + n m t} dt
  5. 5

    Final velocity

    v(t) = (Q E₀ / (n m)) ln(M₀ + n m t) - (Q E₀ / (n m)) ln(M₀) • v(t) = (Q E₀ / (n m)) ln((M₀ + n m t) / M₀)
    v(t)=QE0nmln⁡(M0+nmtM0)v(t) = \frac{Q E_0}{n m} \ln\left(\frac{M_0 + n m t}{M_0}\right)

Final answer

v(t) = (Q E₀ t) / (M₀ + n m t)

Remember: Variable mass systems need careful application of Newton's second law.

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In a variable mass system, if the external force is zero and mass is being ejected, what happens to the velocity of the main body?

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