Algebra

JEE Main level, single correct, medium

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Question 2 of 6

The sum of the infinite geometric series 1+13+19+127+…1 + \frac{1}{3} + \frac{1}{9} + \frac{1}{27} + \dots is:

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Answer: (B) 3/23/2

S∞=a1−r=11−1/3=12/3=32S_\infty = \frac{a}{1 - r} = \frac{1}{1 - 1/3} = \frac{1}{2/3} = \frac{3}{2}.

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