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Algebra

JEE Main level, single correct, medium

3 of 6

Question 3 of 6

The term independent of $x$ in the expansion of $\left( x + \frac{1}{x} \right)^{10}$ is:

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Answer: (C) $^{10}C_5$

General term

T_{r+1} = ^{10}C_r x^{10-r} (x^{-1})^r = ^{10}C_r x^{10-2r}

. For independent of

x

10-2r = 0 \implies r=5

. Coefficient is

^{10}C_5

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JEE Main 2025 Apr 2 Shift 1 question paper

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JEE Main Mathematics practice question on Algebra, with the answer and a step-by-step solution. Scan a question from your own book or paper to get a whiteboard video.

The term independent of xxx in the expansion of (x+1x)10\left( x + \frac{1}{x} \right)^{10}(x+x1​)10 is:

JEE Main question paper PDF

More Mathematics practice

The term independent of $x$ in the expansion of $\left( x + \frac{1}{x} \right)^{10}$ is: