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Calculus

JEE Main level, single correct, medium

2 of 4

Question 2 of 4

The integrating factor of the differential equation $\frac{dy}{dx} + \frac{2}{x} y = x^2$ ( $x > 0$ ) is:

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Answer: (B) $x^2$

\text{IF} = e^{\int \frac{2}{x} dx} = e^{2\ln x} = e^{\ln x^2} = x^2

JEE Main question paper PDF

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JEE Main 2025 Apr 2 Shift 1 question paper

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JEE Main Mathematics practice question on Calculus, with the answer and a step-by-step solution. Scan a question from your own book or paper to get a whiteboard video.

The integrating factor of the differential equation dydx+2xy=x2\frac{dy}{dx} + \frac{2}{x} y = x^2dxdy​+x2​y=x2 (x>0x > 0x>0) is:

JEE Main question paper PDF

More Mathematics practice

The integrating factor of the differential equation $\frac{dy}{dx} + \frac{2}{x} y = x^2$ ( $x > 0$ ) is: