Doubtclip is an AI tutor that turns any homework or exam doubt into a step-by-step whiteboard video lesson with diagrams, formulas, and voice explanation.

Which subjects and exams does it support?

It supports Physics, Chemistry, Mathematics/Calculus and related STEM doubts for school boards, JEE, NEET, and global high-school / undergrad practice.

How do I get a video solution?

Upload a photo of the question or paste the text, sign in, and Doubtclip generates a whiteboard-style explanation video you can watch and share.

Is Doubtclip available worldwide?

Yes. Doubtclip is a web app for students globally. Lessons are available in English and Hinglish.

Alternating Current

JEE Main level, single correct, medium

14 of 190

Question 14 of 190

An AC voltage $V=20\sin 200\pi t$ is applied to a series LCR circuit which drives a current $I=10\sin \left(200\pi t+\dfrac{\pi }{3}\right)$ . The average power dissipated is:

Show answer and solution

Answer: (D) $50W$

The average power dissipated is,

\lt P\gt =IV\cos \phi

=\dfrac{10}{\sqrt{2}}\times \dfrac{20}{\sqrt{2}}\times \cos 60^{\circ}

=50W

JEE Main question paper PDF

Open a shift to read the full paper on this page, or download it.

JEE Main 2025 Apr 2 Shift 1 question paper

Open Download PDF

Opening paper…

Explain it as a whiteboard videoStep-by-step, in Hinglish or English. Your first video needs no login.Solved it on paper but got it wrong?Upload a photo of your working. Mistake Doctor marks the exact line that broke.

See it move: AC circuits, phasors and resonance simulationDrag the sliders and watch the numbers in this question change.

More Physics practice

JEE Main Physics practice question on Alternating Current (Alternating Current, Voltage and Power), with the answer and a step-by-step solution. Scan a question from your own book or paper to get a whiteboard video.

An AC voltage V=20sin⁡200πtV=20\sin 200\pi tV=20sin200πt is applied to a series LCR circuit which drives a current I=10sin⁡(200πt+π3)I=10\sin \left(200\pi t+\dfrac{\pi }{3}\right)I=10sin(200πt+3π​). The average power dissipated is:

JEE Main question paper PDF

More Physics practice

An AC voltage $V=20\sin 200\pi t$ is applied to a series LCR circuit which drives a current $I=10\sin \left(200\pi t+\dfrac{\pi }{3}\right)$ . The average power dissipated is: