Alternating Current

JEE Main level, numerical answer, medium

30 of 190

Question 30 of 190

At very high frequencies, the effective impedance of the given circuit will be _________Ω.\Omega .

Show answer and solution

Answer: 2

For ω→∞\omega \rightarrow \infty
1ωC→0⇒\dfrac{1}{\omega C}\rightarrow 0\Rightarrow capacitance acts as short circuit
&
ωL→∞\omega L\rightarrow \infty Inductance acts as open circuit

Z=1+2×22+2=2ΩZ=1+\dfrac{2\times 2}{2+2}=2\Omega

JEE Main question paper PDF

Open a shift to read the full paper on this page, or download it.

JEE Main 2025 Apr 2 Shift 1 question paper

Open Download PDF

Opening paper…

Explain it as a whiteboard videoStep-by-step, in Hinglish or English. Your first video needs no login.Solved it on paper but got it wrong?Upload a photo of your working. Mistake Doctor marks the exact line that broke.
See it move: AC circuits, phasors and resonance simulationDrag the sliders and watch the numbers in this question change.

More Physics practice

JEE Main Physics practice question on Alternating Current (Alternating Current, Voltage and Power), with the answer and a step-by-step solution. Scan a question from your own book or paper to get a whiteboard video.