Alternating Current

JEE Main level, single correct, medium

70 of 190

Question 70 of 190

A series LCR circuit is subjected to an ac signal of 200 V,50 Hz200 \mathrm{~V}, 50 \mathrm{~Hz}. If the voltage across the inductor (L=10mH)(\mathrm{L}=10 \mathrm{mH}) is 31.4 V31.4 \mathrm{~V}, then the current in this circuit is _____ .

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Answer: (C) 10 A10 \mathrm{~A}

 Voltage across inductor VL=IXL31.4=I[Lω]31.4=I[L(2πf)]31.4=I[10×10−3(2×3.14)×50⇒I=10 A\begin{aligned} & \text { Voltage across inductor } \mathrm{V}_{\mathrm{L}}=\mathrm{IX}_{\mathrm{L}} \\ & 31.4=\mathrm{I}[\mathrm{L} \omega] \\ & 31.4=\mathrm{I}[\mathrm{L}(2 \pi \mathrm{f})] \\ & 31.4=\mathrm{I}\left[10 \times 10^{-3}(2 \times 3.14) \times 50\right. \\ & \Rightarrow \mathrm{I}=10 \mathrm{~A}\end{aligned}

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