Question 74 of 190

In the given figure, the charge stored in $6\mu F$ capacitor, when points $A$ and $B$ are joined by a connecting wire is _______$\mu C$.

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Answer: 36

At steady state, capacitor behaves as an open circuit and current flows in circuit as shown in the diagram.

${R}_{eq}=9\Omega$
$i=\dfrac{9V}{9\Omega }=1A$
$\Delta {V}_{6\Omega }=1\times 6=6V$
${V}_{A}=3V$
So, potential difference across $6\mu F$ is $6V.$
Hence, $Q=C\Delta V$
$=6\times 6\times {10}^{-6}C$
$=36\mu C$

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