Doubtclip is an AI tutor that turns any homework or exam doubt into a step-by-step whiteboard video lesson with diagrams, formulas, and voice explanation.

Which subjects and exams does it support?

It supports Physics, Chemistry, Mathematics/Calculus and related STEM doubts for school boards, JEE, NEET, and global high-school / undergrad practice.

How do I get a video solution?

Upload a photo of the question or paste the text, sign in, and Doubtclip generates a whiteboard-style explanation video you can watch and share.

Is Doubtclip available worldwide?

Yes. Doubtclip is a web app for students globally. Lessons are available in English and Hinglish.

Alternating Current

JEE Main level, numerical answer, medium

80 of 190

Question 80 of 190

A series LCR circuit is connected to an ac source of $220V,50Hz$ . The circuit contain a resistance $R=100\Omega$ and an inductor of inductive reactance ${X}_{L}=79.6\Omega$ . The capacitance of the capacitor needed to maximize the average rate at which energy is supplied will be ______ $\mu F$ .

Show answer and solution

Answer: 40

The average rate at which energy supplied i.e. power delivered is maximum in case of the resonance, therefore

{X}_{C}={X}_{L}

\Rightarrow \dfrac{1}{\omega C}=79.6\Omega

\Rightarrow C=\dfrac{1}{\omega \times 79.6} =\dfrac{1}{2\pi f\times 79.6} =\dfrac{1}{100\pi \times 79.6} =40\mu F

Hence,

C=40\mu F

JEE Main question paper PDF

Open a shift to read the full paper on this page, or download it.

JEE Main 2025 Apr 2 Shift 1 question paper

Open Download PDF

Opening paper…

Explain it as a whiteboard videoStep-by-step, in Hinglish or English. Your first video needs no login.Solved it on paper but got it wrong?Upload a photo of your working. Mistake Doctor marks the exact line that broke.

See it move: AC circuits, phasors and resonance simulationDrag the sliders and watch the numbers in this question change.

More Physics practice

JEE Main Physics practice question on Alternating Current (AC Circuits), with the answer and a step-by-step solution. Scan a question from your own book or paper to get a whiteboard video.