Question 82 of 190

In the given circuit, $rms$ value of current $\left({I}_{rms}\right)$ through the resistor $R$ is :

A$2A$B$\dfrac{1}{2}A$C$20A$D$2\sqrt{2}A$

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Answer: (A) $2A$

Impedance of the given LCR circuit will be, $Z=\sqrt{{R}^{2}+{\left({X}_{L}-{X}_{C}\right)}^{2}} \Rightarrow Z=\sqrt{{100}^{2}+{\left(200-100\right)}^{2}}$
$=100\sqrt{2}\Omega$
Therefore, RMS current can be written as,
${I}_{rms}=\dfrac{{V}_{rms}}{Z}=\dfrac{200\sqrt{2}}{100\sqrt{2}}$
$=2A$

JEE Main Physics practice question on Alternating Current (AC Circuits), with the answer and a step-by-step solution. Scan a question from your own book or paper to get a whiteboard video.