Question 93 of 190

The effective current $I$ in the given circuit at very high frequencies will be _____ $A$.

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Answer: 44

At very high frequencies, inductor acts as an open circuit and capacitor as short circuit.
So, capacitive reactance, ${X}_{C}=\dfrac{1}{\omega C}\approx 0$
Also, inductive reactance, ${X}_{L}=\omega L\approx \infty$
Thus, equivalent circuit can be redrawn as

Here, both $4\Omega$ resistances are in parallel and together they are in series with$1\Omega$ and $2\Omega$ resistances.
Equivalent impedance is $Z=1+\dfrac{4\times 4}{4+4}+2=5\Omega$
Effective current is $I=\dfrac{220V}{5\Omega }=44A$

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