Alternating Current

JEE Main level, single correct, medium

112 of 190

Question 112 of 190

For a series LCRLCR circuit with R=100Ω,L=0.5mHR=100\Omega ,L=0.5mH and C=0.1pFC=0.1pF connected across 220V−50Hz220V-50Hz ACAC supply, the phase angle between
current and supplied voltage and the nature of the circuit is:

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Answer: (D) ≈90∘,\approx 90^{\circ}, predominantly capacitive circuit

R=100ΩR=100\Omega
XL=ωL=50π×10−3{X}_{L}=\omega L=50\pi \times {10}^{-3}
XC=1ωC=1011100π{X}_{C}=\dfrac{1}{\omega C}=\dfrac{{10}^{11}}{100\pi }
XC≫XL{X}_{C}≫{X}_{L}
and ∣XC−XL∣≫R\left|{X}_{C}-{X}_{L}\right|≫R

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