Alternating Current

JEE Main level, numerical answer, medium

123 of 190

Question 123 of 190

A series LCR circuit is designed to resonate at an angular frequency ω0=105rads−1.{\omega }_{0}={10}^{5}rad{s}^{-1}. The circuit draws 16W16W power from 120V120V source at resonance. The value of resistance RR in the circuit is ________ Ω.\Omega .

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Answer: 900

At resonance
P=V2RP=\dfrac{{V}^{2}}{R}
R=V2P=(120)216R=\dfrac{{V}^{2}}{P}=\dfrac{{\left(120\right)}^{2}}{16}
=900Ω=900\Omega

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