Alternating Current

JEE Main level, single correct, medium

156 of 190

Question 156 of 190

In a series resonant LCR circuit, the voltage across RR is 100 volts and R=1kΩR=1 \mathrm{k} \Omega with C=2μFC=2 \mu \mathrm{F}. The resonant frequency ω\omega is 200rad/s200 \mathrm{rad} / \mathrm{s}. At resonance the voltage across LL is

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Answer: (D) 250 V250 \mathrm{~V}

i=1001000=0.1 A\mathrm{i}=\frac{100}{1000}=0.1 \mathrm{~A}
VL=VC=0.1200×2×10−6=250 VV_L=V_C=\frac{0.1}{200 \times 2 \times 10^{-6}}=250 \mathrm{~V}

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