Alternating Current

JEE Main level, single correct, medium

182 of 190

Question 182 of 190

A transformer consisting of 300300 turns in the primary and 150150 turns in the secondary gives output power of 2.2kW2.2kW . If the current in the secondary coil is 10A10A , then the input voltage and current in the primary coil are:

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Answer: (C) 440V440V and 5A5A

Assuming 100% efficiency,
V2V1=i1i2=N2N1\dfrac{{V}_{2}}{{V}_{1}}=\dfrac{{i}_{1}}{{i}_{2}}=\dfrac{{N}_{2}}{{N}_{1}}
i1i2=N2N1i110=150300i1=5A\dfrac{{i}_{1}}{{i}_{2}}=\dfrac{{N}_{2}}{{N}_{1}} \dfrac{{i}_{1}}{10}=\dfrac{150}{300} {i}_{1}=5A
P=VI2200=5×V1V1=440VP=VI 2200=5\times {V}_{1} {V}_{1}=440V

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