Alternating Current

JEE Main level, single correct, medium

187 of 190

Question 187 of 190

In a transformer, number of turns in the primary coil are 140 and that in the secondary coil are 280. If current in primary coil is 4 A4 \mathrm{~A}, then that in the secondary coil is

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Answer: (B) 2 A

I1N1=I2N2⇒I2=4×140280=2 AI_1 N_1=I_2 N_2 \Rightarrow I_2=\frac{4 \times 140}{280}=2 \mathrm{~A}

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