Alternating Current

JEE Main level, single correct, medium

190 of 190

Question 190 of 190

The figure shows a circuit that contains four identical resistors with resistance R=2.0Ω,R=2.0\Omega , two identical inductors with inductance L=2.0mHL=2.0mH and an ideal battery with E.M.F. E=9V.E=9V. The current ii just after the switch SS is closed will be:

Show answer and solution

Answer: (C) 2.25A2.25A

Just after the switch is closed, inductor will behave like infinite resistance (open circuit) so the circuit will look like

i=9R+R=94=2.25Ai=\dfrac{9}{R+R}=\dfrac{9}{4}=2.25A

JEE Main question paper PDF

Open a shift to read the full paper on this page, or download it.

JEE Main 2025 Apr 2 Shift 1 question paper

Open Download PDF

Opening paper…

Explain it as a whiteboard videoStep-by-step, in Hinglish or English. Your first video needs no login.Solved it on paper but got it wrong?Upload a photo of your working. Mistake Doctor marks the exact line that broke.
See it move: AC circuits, phasors and resonance simulationDrag the sliders and watch the numbers in this question change.

More Physics practice

JEE Main Physics practice question on Alternating Current (Parallel AC Circuits), with the answer and a step-by-step solution. Scan a question from your own book or paper to get a whiteboard video.