Atoms & Nuclei

JEE Main level, single correct, medium

80 of 239

Question 80 of 239

The energy required to remove the electron from a singly ionized Helium atom is 2.22.2 times the energy required to remove an electron from Helium atom. The total energy required to ionize the Helium atom completely is:

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Answer: (B) 79eV79 \mathrm{eV}

Energy required to remove e−\mathrm{e}^{-}from singly ionized helium atom =(13.6)Z212=54.4eV=\frac{(13.6) Z^2}{1^2}=54.4 \mathrm{eV} (∵Z=2)(\because \mathrm{Z}=2) Energy required to remove e−\mathrm{e}^{-}from helium atom =xeV=x \mathrm{eV}
According to question, 54.4eV=2.2x⇒x54.4 \mathrm{eV}=2.2 \mathrm{x} \Rightarrow \mathrm{x} =24.73eV=24.73 \mathrm{eV}
Therefore, energy required to ionize helium atom =(54.4+24.73)eV=79.12eV=(54.4+24.73) \mathrm{eV}=79.12 \mathrm{eV}

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