Atoms & Nuclei

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110 of 239

Question 110 of 239

The minimum energy required by a hydrogen atom in ground state to emit radiation in Balmer series is nearly :

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Answer: (D) 12.1eV12.1eV

For Balmer series, transition is from n=3,4,5,6,etcn=3,4,5,6,etc to n=2n=2.
For transition to n=2n=2, the minimum state to transition from is n=3n=3.
Therefore, energy required ΔE=E3−E1=−13.69−(−13.6)=12.1eV\Delta E={E}_{3}-{E}_{1}=-\dfrac{13.6}{9}-\left(-13.6\right)=12.1eV

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