Atoms & Nuclei

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Question 152 of 239

The electron of a hydrogen atom makes a transition from the (n+1)th (n+1)^{\text {th }} orbit to the nth n^{\text {th }} orbit. For large n\mathrm{n} the wavelength of the emitted radiation is proportional to

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Answer: (B) n3n^3

If n1=nn_1=n and n2=n+1n_2=n+1 Maximum wavelength λmax⁡=n2(n+12)(2n+1R)\lambda_{\max }=\frac{n^2\left(n+1^2\right)}{(2 n+1 R)}
Therefore, for large n,λmax⁡∝n3\mathrm{n}, \lambda_{\max } \propto n^3

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