Question 55 of 180

In the figure shown below, the charge on the left plate of the 10F capacitor is -30C. The charge on the right plate of the 6F capacitor is:

A$-12 \mu \mathrm{C}$B$+12 \mu \mathrm{C}$C$-18 \mu \mathrm{C}$D$+18 \mu \mathrm{C}$

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Answer: (D) $+18 \mu \mathrm{C}$

As given in the figure, $6 \mu \mathrm{F}$ and $4 \mu \mathrm{F}$ are in parallel. Now using charge conservation

Charge on $6 \mu F$ capacitor $=\frac{6}{6+4} \times 30=18 \mu C$

Since charge is asked on right plate therefore is $+18 \mu C$

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