Experimental Physics

JEE Main level, single correct, medium

12 of 70

Question 12 of 70

There are 100 divisions on the circular scale of a screw gauge of pitch 1 mm1 \mathrm{~mm}. With no measuring quantity in between the jaws, the zero of the circular scale lies 5 divisions below the reference line. The diameter of a wire is then measured using this screw gauge. It is found that 4 linear scale divisions are clearly visible while 60 divisions on circular scale coincide with the reference line. The diameter of the wire is :

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Answer: (C) 4.55 mm4.55 \mathrm{~mm}

 Least count =1100 mm=0.01 mm zero error =+0.05 mm Reading =4×1 mm+60×0.01 mm−0.05 mm=4.55 mm\begin{aligned} & \text { Least count }=\frac{1}{100} \mathrm{~mm}=0.01 \mathrm{~mm} \\ & \text { zero error }=+0.05 \mathrm{~mm} \\ & \text { Reading }=4 \times 1 \mathrm{~mm}+60 \times 0.01 \mathrm{~mm}-0.05 \mathrm{~mm} \\ & =4.55 \mathrm{~mm}\end{aligned}

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