Experimental Physics

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18 of 70

Question 18 of 70

1010 divisions on the main scale of a Vernier calliper coincide with 1111 divisions on the Vernier scale. If each division on the main scale is of 55 units, the least count of the instrument is :

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Answer: (D) 511\dfrac{5}{11}

Given:
10MSD=11VSD10MSD=11VSD
⇒1VSD=1011MSD\Rightarrow 1VSD=\dfrac{10}{11}MSD
LC=1MSD−1VSDLC=1MSD-1VSD
=1MSD−1011MSD=1MSD-\dfrac{10}{11}MSD
=1MSD11=\dfrac{1MSD}{11}
=511=\dfrac{5}{11} units

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