Experimental Physics

JEE Main level, single correct, medium

23 of 70

Question 23 of 70

In an experiment with vernier callipers of least count 0.1mm0.1mm, when two jaws are joined together the zero of vernier scale lies right to the zero of the main scale and 6th{6}^{th} division of vernier scale coincides with the main scale division. While measuring the diameter of a spherical bob, the zero of vernier scale lies in between 3.2cm3.2cm and 3.3cm3.3cm marks and 4th{4}^{th} division of vernier scale coincides with the main scale division. The diameter of bob is measured as

Show answer and solution

Answer: (B) 3.18cm3.18cm

The least count is LC=0.1mmLC=0.1mm
Zero error
(ZE)=6×LC=6×0.1mm=0.6mm(ZE)=6\times LC=6\times 0.1mm=0.6mm
The total reading is
TR=MSR+(VSR×LC)−ZE⇒TR=32mm+(0.1×4)mm−0.6mm⇒TR=31.8mm=3.18cmTR=MSR+\left(VSR\times LC\right)-ZE \Rightarrow TR=32mm+(0.1\times 4)mm-0.6mm \Rightarrow TR=31.8mm=3.18cm

JEE Main question paper PDF

Open a shift to read the full paper on this page, or download it.

JEE Main 2025 Apr 2 Shift 1 question paper

Open Download PDF

Opening paper…

Explain it as a whiteboard videoStep-by-step, in Hinglish or English. Your first video needs no login.Solved it on paper but got it wrong?Upload a photo of your working. Mistake Doctor marks the exact line that broke.
Revise Modern Physics firstFormula sheet, solved examples and the traps students fall into.

More Physics practice

JEE Main Physics practice question on Experimental Physics (Experimental Physics), with the answer and a step-by-step solution. Scan a question from your own book or paper to get a whiteboard video.