Experimental Physics

JEE Main level, numerical answer, medium

35 of 70

Question 35 of 70

In a vernier callipers, each cmcm on the main scale is divided into 2020 equal parts. If tenth vernier scale division coincides with nineth main scale division. Then the value of vernier constant will be _____ ×10−2mm\times {10}^{-2}mm

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Answer: 5

Vernier constant is defined as the difference between the value of one main scale division and one vernier scale division. It is also known as the least count of vernier calliper.
The main scale division of the given vernier calliper is MSD=1cm20=0.5mmMSD=\dfrac{1cm}{20}=0.5mm.
LC=MSDn=0.5mm10=0.05mm=5×10−2mmLC=\dfrac{MSD}{n}=\dfrac{0.5mm}{10}=0.05mm=5\times {10}^{-2}mm

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